5x^2+48=(x-1)(5x+6)

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Solution for 5x^2+48=(x-1)(5x+6) equation: 



5x^2+48=(x-1)(5x+6)

We move all terms to the left:

5x^2+48-((x-1)(5x+6))=0

We multiply parentheses ..

5x^2-((+5x^2+6x-5x-6))+48=0



We calculate terms in parentheses: -((+5x^2+6x-5x-6)), so:

(+5x^2+6x-5x-6)

We get rid of parentheses

5x^2+6x-5x-6

We add all the numbers together, and all the variables

5x^2+x-6

Back to the equation:

-(5x^2+x-6)



We get rid of parentheses

5x^2-5x^2-x+6+48=0

We add all the numbers together, and all the variables

-1x+54=0

We move all terms containing x to the left, all other terms to the right

-x=-54

x=-54/-1

x=+54

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